MAS-I · Statistics · Free Lesson

Model insurance claim frequency and severity.

Free CAS MAS-I (Modern Actuarial Statistics I) lesson in Statistics. 16 min read, ~2,356 words.

A pricing actuary needs two pieces to set a premium: how often claims happen and how big they are when they do. Frequency and severity each have their own distributional toolbox, and MAS-I tests both fluently.

Frequency distributions. Claim counts are non-negative integers, so the candidate distributions are discrete.

Poisson(λ\lambda): P(N=k)=e−λλk/k!P(N=k) = e^{-\lambda}\lambda^k/k!, with mean and variance both equal to λ\lambda. Use when arrivals are independent and the portfolio is homogeneous.

Negative binomial(r,βr,\beta): mean rβr\beta, variance rβ(1+β)r\beta(1+\beta). Variance exceeds the mean by factor (1+β)(1+\beta). It arises as a gamma-mixed Poisson, so it is the default when policyholders vary in underlying risk.

Binomial(m,qm,q): mean mqmq, variance mq(1−q)mq(1-q). Variance is below the mean. Appropriate when the count is bounded (claims per policy capped at mm).

KEY: Compare sample mean and variance first. Var/Mean<1\text{Var}/\text{Mean}<1 suggests binomial, ≈1\approx 1 suggests Poisson, >1>1 suggests negative binomial.

The (a,b,0)(a,b,0) class. All three satisfy pk/pk−1=a+b/kp_k/p_{k-1} = a + b/k for constants a,ba,b. Poisson has a=0,b=λa=0,b=\lambda; negative binomial has a=β/(1+β),b=(r−1)β/(1+β)a=\beta/(1+\beta),b=(r-1)\beta/(1+\beta); binomial has a=−q/(1−q),b=(m+1)q/(1−q)a=-q/(1-q),b=(m+1)q/(1-q).

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Bottom line

Exam shortcut

When the question gives a sample mean and variance for counts, compute the ratio first. The answer family is decided before you reach for a formula. For aggregate-loss problems, write E[S]E[S] and Var(S)\text{Var}(S) using the general two-term formula, then simplify only if NN is Poisson.

The full lesson (about 2,356 words, 16 min read) adds 8 worked examples, all 6 common mistakes, a self-check, free in the app.

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