Exam FAM · Present Value Random Variables for Long-Term Insurance Coverages · Free Lesson

Relationships Between Insurance, Endowment, and Annuity Present Values

Free SOA Exam FAM (Fundamentals of Actuarial Mathematics) lesson in Present Value Random Variables for Long-Term Insurance Coverages. 11 min read, ~1,605 words.

Problem Preview: Given a¨45=16 \ddot{a}_{45} = 16 , a¨65=10 \ddot{a}_{65} = 10 , 20E45=0.30 {}_{20}E_{45} = 0.30 , d=0.05 d = 0.05 . Find the 20-year term insurance. Three identities, 30 seconds: temporary annuity = 16−0.30×10=13 16 - 0.30 \times 10 = 13 . Endowment = 1−0.05×13=0.35 1 - 0.05 \times 13 = 0.35 . Term = 0.35−0.30=0.05 0.35 - 0.30 = 0.05 . Summing 20 individual terms would take five minutes.

HIGH-FREQUENCY: The insurance-annuity identity Ax=1−da¨x A_x = 1 - d\ddot{a}_x appears directly or indirectly in the majority of Topics 9 and 10 problems.

From Y=(1−Z)/d Y = (1-Z)/d , taking expectations:

a¨x=1−Axd,Ax=1−d⋅a¨x\ddot{a}_x = \frac{1-A_x}{d}, \quad A_x = 1 - d \cdot \ddot{a}_x

Continuous: Aˉx=1−δ⋅aˉx \bar{A}_x = 1 - \delta \cdot \bar{a}_x . The pattern: insurance = 1 minus (discount rate) times (annuity-due).

KEY: The identity Ax=1−da¨x A_x = 1 - d\ddot{a}_x appears directly or indirectly in the majority of Topics 9 and 10 problems. Match the discount rate to the payment type: d d for due, δ \delta for continuous, d(m) d^{(m)} for m m -thly.

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If your approach requires summing more than 5 terms, stop and look for an identity. The exam frequently provides a¨x \ddot{a}_x , a¨x+n \ddot{a}_{x+n} , and nEx {}_{n}E_x , three values that give you the temporary annuity, endowment insurance, and term insurance through simple arithmetic. "1 minus d-a-double-dot", the insurance-annuity identity in one phrase. "Whole = Temp + Deferred." "Endowment = Term + Pure."

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