Free GARP FRM Part II Credit Risk Practice Questions

Practice 86 free Credit Risk questions for GARP FRM Part II.

86 Questions
28 Easy
37 Medium
21 Hard
2026 Syllabus

Sample Questions

Question 1 Easy
Assume a corporate issuer has a constant hazard rate of default of 0.04 per year. What is the probability that the issuer survives the next three years?
Solution
D is correct. Under a constant hazard rate λ\lambda, the survival probability over horizon tt is S(t)=eλtS(t) = e^{-\lambda t}. With λ=0.04\lambda = 0.04 and t=3t = 3, S(3)=e0.120.8869S(3) = e^{-0.12} \approx 0.8869.
Question 2 Medium
A counterparty's default time follows a constant hazard rate λ=0.05\lambda = 0.05 per year. What is the unconditional probability that the counterparty defaults within the next four years?
Solution
B is correct. Under a constant hazard rate, survival to time tt is S(t)=eλtS(t) = e^{-\lambda t}. The cumulative default probability over four years is 1S(4)=1eλt=1e0.05×4=1e0.20=10.8187=0.18131 - S(4) = 1 - e^{-\lambda t} = 1 - e^{-0.05 \times 4} = 1 - e^{-0.20} = 1 - 0.8187 = 0.1813, or 18.13%.
Question 3 Hard
Two corporate obligors A and B each have a one-year unconditional default probability of 5%. The default correlation between them is 0.30. Treating each default as a Bernoulli indicator, what is the probability that both A and B default within one year?
Solution
B is correct. Default correlation is the correlation between the Bernoulli default indicators, so by definition ρD=P(AB)PAPBPA(1PA)PB(1PB).\rho_D = \frac{P(A \cap B) - P_A P_B}{\sqrt{P_A(1-P_A) \cdot P_B(1-P_B)}}. Solving for the joint default probability, P(AB)=ρDPA(1PA)PB(1PB)+PAPB.P(A \cap B) = \rho_D \sqrt{P_A(1-P_A) \cdot P_B(1-P_B)} + P_A P_B. With PA=PB=0.05P_A = P_B = 0.05 and ρD=0.30\rho_D = 0.30, the indicator standard deviation is 0.05×0.95=0.2179\sqrt{0.05 \times 0.95} = 0.2179, so P(AB)=0.30×(0.2179)2+(0.05)2=0.30×0.0475+0.0025=0.01425+0.0025=0.01675.P(A \cap B) = 0.30 \times (0.2179)^2 + (0.05)^2 = 0.30 \times 0.0475 + 0.0025 = 0.01425 + 0.0025 = 0.01675. The joint default probability is approximately 1.675%.

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